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1453446302137 is a prime number
BaseRepresentation
bin10101001001101000001…
…001101000100110111001
312010221121011122020212121
4111021220021220212321
5142303124223132022
63031412022241241
7210002516503624
oct25115011504671
95127534566777
101453446302137
11510448601125
121b5830286221
13a70a066191b
14504c091adbb
1527c1a3562c7
hex152682689b9

1453446302137 has 2 divisors, whose sum is σ = 1453446302138. Its totient is φ = 1453446302136.

The previous prime is 1453446302107. The next prime is 1453446302149. The reversal of 1453446302137 is 7312036443541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1212066681721 + 241379620416 = 1100939^2 + 491304^2 .

It is a cyclic number.

It is not a de Polignac number, because 1453446302137 - 239 = 903690488249 is a prime.

It is a super-2 number, since 2×14534463021372 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1453446302093 and 1453446302102.

It is not a weakly prime, because it can be changed into another prime (1453446302107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726723151068 + 726723151069.

It is an arithmetic number, because the mean of its divisors is an integer number (726723151069).

Almost surely, 21453446302137 is an apocalyptic number.

It is an amenable number.

1453446302137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1453446302137 is an equidigital number, since it uses as much as digits as its factorization.

1453446302137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 725760, while the sum is 43.

The spelling of 1453446302137 in words is "one trillion, four hundred fifty-three billion, four hundred forty-six million, three hundred two thousand, one hundred thirty-seven".