Base | Representation |
---|---|
bin | 10101001001110010101… |
… | …110011001110100011011 |
3 | 12010222001112110122220012 |
4 | 111021302232121310123 |
5 | 142304010132304201 |
6 | 3031441400552135 |
7 | 210010102456616 |
oct | 25116256316433 |
9 | 5128045418805 |
10 | 1453623713051 |
11 | 510529765614 |
12 | 1b587b78264b |
13 | a70cb33a1b3 |
14 | 504da2dd17d |
15 | 27c2abec5bb |
hex | 15272b99d1b |
1453623713051 has 2 divisors, whose sum is σ = 1453623713052. Its totient is φ = 1453623713050.
The previous prime is 1453623713021. The next prime is 1453623713077. The reversal of 1453623713051 is 1503173263541.
It is a strong prime.
It is an emirp because it is prime and its reverse (1503173263541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1453623713051 - 210 = 1453623712027 is a prime.
It is a super-2 number, since 2×14536237130512 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1453623713021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726811856525 + 726811856526.
It is an arithmetic number, because the mean of its divisors is an integer number (726811856526).
Almost surely, 21453623713051 is an apocalyptic number.
1453623713051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1453623713051 is an equidigital number, since it uses as much as digits as its factorization.
1453623713051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 226800, while the sum is 41.
Adding to 1453623713051 its reverse (1503173263541), we get a palindrome (2956796976592).
The spelling of 1453623713051 in words is "one trillion, four hundred fifty-three billion, six hundred twenty-three million, seven hundred thirteen thousand, fifty-one".
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