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145401326177 is a prime number
BaseRepresentation
bin1000011101101010011…
…0000010101001100001
3111220022021020200022212
42013122212002221201
54340240214414202
6150444011011505
713335115610642
oct2073246025141
9456267220285
10145401326177
1156734292478
122421a739b95
13109329079a3
147074b1b6c9
153baeeee652
hex21da982a61

145401326177 has 2 divisors, whose sum is σ = 145401326178. Its totient is φ = 145401326176.

The previous prime is 145401326173. The next prime is 145401326207. The reversal of 145401326177 is 771623104541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82713184801 + 62688141376 = 287599^2 + 250376^2 .

It is a cyclic number.

It is not a de Polignac number, because 145401326177 - 22 = 145401326173 is a prime.

It is a super-2 number, since 2×1454013261772 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145401326173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72700663088 + 72700663089.

It is an arithmetic number, because the mean of its divisors is an integer number (72700663089).

Almost surely, 2145401326177 is an apocalyptic number.

It is an amenable number.

145401326177 is a deficient number, since it is larger than the sum of its proper divisors (1).

145401326177 is an equidigital number, since it uses as much as digits as its factorization.

145401326177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 141120, while the sum is 41.

The spelling of 145401326177 in words is "one hundred forty-five billion, four hundred one million, three hundred twenty-six thousand, one hundred seventy-seven".