14540211451 has 2 divisors, whose sum is σ = 14540211452. Its totient is φ = 14540211450.

The previous prime is 14540211397. The next prime is 14540211463. The reversal of 14540211451 is 15411204541.

14540211451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (15411204541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14540211451 - 2⁹ = 14540210939 is a prime.

It is a super-2 number, since 2×14540211451² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14540211251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270105725 + 7270105726.

It is an arithmetic number, because the mean of its divisors is an integer number (7270105726).

Almost surely, 2^14540211451 is an apocalyptic number.

14540211451 is a deficient number, since it is larger than the sum of its proper divisors (1).

14540211451 is an equidigital number, since it uses as much as digits as its factorization.

14540211451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3200, while the sum is 28.

Adding to 14540211451 its reverse (15411204541), we get a palindrome (29951415992).

The spelling of 14540211451 in words is "fourteen billion, five hundred forty million, two hundred eleven thousand, four hundred fifty-one".