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145403400143 = 595324425231
BaseRepresentation
bin1000011101101010110…
…1111100111111001111
3111220022102011001021102
42013122231330333033
54340241232301033
6150444123253315
713335142336331
oct2073255747717
9456272131242
10145403400143
11567354796a1
122421b37a23b
13109331829a1
1470750db451
153bb02adde8
hex21dab7cfcf

145403400143 has 4 divisors (see below), whose sum is σ = 145427831328. Its totient is φ = 145378968960.

The previous prime is 145403400139. The next prime is 145403400169. The reversal of 145403400143 is 341004304541.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145403400143 - 22 = 145403400139 is a prime.

It is a super-2 number, since 2×1454034001432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145403400133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12206663 + ... + 12218568.

It is an arithmetic number, because the mean of its divisors is an integer number (36356957832).

Almost surely, 2145403400143 is an apocalyptic number.

145403400143 is a deficient number, since it is larger than the sum of its proper divisors (24431185).

145403400143 is an equidigital number, since it uses as much as digits as its factorization.

145403400143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24431184.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 145403400143 its reverse (341004304541), we get a palindrome (486407704684).

The spelling of 145403400143 in words is "one hundred forty-five billion, four hundred three million, four hundred thousand, one hundred forty-three".

Divisors: 1 5953 24425231 145403400143