145410105030341 has 4 divisors (see below), whose sum is σ = 145422399800352. Its totient is φ = 145397810260332.

The previous prime is 145410105030277. The next prime is 145410105030347. The reversal of 145410105030341 is 143030501014541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 145410105030341 - 2⁶ = 145410105030277 is a prime.

It is a super-2 number, since 2×145410105030341² (a number of 29 digits) contains 22 as substring.

It is an alternating number because its digits alternate between odd and even.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145410105030298 and 145410105030307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145410105030347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6147367265 + ... + 6147390918.

It is an arithmetic number, because the mean of its divisors is an integer number (36355599950088).

Almost surely, 2^{145410105030341} is an apocalyptic number.

It is an amenable number.

145410105030341 is a deficient number, since it is larger than the sum of its proper divisors (12294770011).

145410105030341 is a wasteful number, since it uses less digits than its factorization.

145410105030341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12294770010.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 145410105030341 its reverse (143030501014541), we get a palindrome (288440606044882).

The spelling of 145410105030341 in words is "one hundred forty-five trillion, four hundred ten billion, one hundred five million, thirty thousand, three hundred forty-one".