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145411133004 = 22324039198139
BaseRepresentation
bin1000011101101100101…
…1011100111001001100
3111220022221200220202200
42013123023130321030
54340300222224004
6150445001121500
713335265144164
oct2073313347114
9456287626680
10145411133004
1156739880495
1224221a89290
131093495c647
1470761515a4
153bb0cda239
hex21db2dce4c

145411133004 has 18 divisors (see below), whose sum is σ = 367567030740. Its totient is φ = 48470377656.

The previous prime is 145411132981. The next prime is 145411133009. The reversal of 145411133004 is 400331114541.

145411133004 is a `hidden beast` number, since 1 + 4 + 541 + 113 + 3 + 0 + 0 + 4 = 666.

It is a tau number, because it is divible by the number of its divisors (18).

It is a super-2 number, since 2×1454111330042 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (145411133009) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2019599034 + ... + 2019599105.

Almost surely, 2145411133004 is an apocalyptic number.

It is an amenable number.

145411133004 is an abundant number, since it is smaller than the sum of its proper divisors (222155897736).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

145411133004 is a wasteful number, since it uses less digits than its factorization.

145411133004 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4039198149 (or 4039198144 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 145411133004 its reverse (400331114541), we get a palindrome (545742247545).

The spelling of 145411133004 in words is "one hundred forty-five billion, four hundred eleven million, one hundred thirty-three thousand, four".

Divisors: 1 2 3 4 6 9 12 18 36 4039198139 8078396278 12117594417 16156792556 24235188834 36352783251 48470377668 72705566502 145411133004