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145412223403 is a prime number
BaseRepresentation
bin1000011101101100111…
…1100111000110101011
3111220100000202022111211
42013123033213012223
54340301012122103
6150445040333551
713335310335166
oct2073317470653
9456300668454
10145412223403
115673a455747
12242223142b7
1310934c51a55
147076356add
153bb0e5336d
hex21db3e71ab

145412223403 has 2 divisors, whose sum is σ = 145412223404. Its totient is φ = 145412223402.

The previous prime is 145412223391. The next prime is 145412223443. The reversal of 145412223403 is 304322214541.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145412223403 is a prime.

It is a super-2 number, since 2×1454122234032 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145412223443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72706111701 + 72706111702.

It is an arithmetic number, because the mean of its divisors is an integer number (72706111702).

Almost surely, 2145412223403 is an apocalyptic number.

145412223403 is a deficient number, since it is larger than the sum of its proper divisors (1).

145412223403 is an equidigital number, since it uses as much as digits as its factorization.

145412223403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 145412223403 its reverse (304322214541), we get a palindrome (449734437944).

The spelling of 145412223403 in words is "one hundred forty-five billion, four hundred twelve million, two hundred twenty-three thousand, four hundred three".