Base | Representation |
---|---|
bin | 10101001010010000011… |
… | …101100000101000110011 |
3 | 12011000100022012210112001 |
4 | 111022100131200220303 |
5 | 142311020341213021 |
6 | 3032003101514431 |
7 | 210025341112513 |
oct | 25122035405063 |
9 | 5130308183461 |
10 | 1454122601011 |
11 | 510765332513 |
12 | 1b599a872a17 |
13 | a717a7c3082 |
14 | 50546685843 |
15 | 27c598e6091 |
hex | 15290760a33 |
1454122601011 has 2 divisors, whose sum is σ = 1454122601012. Its totient is φ = 1454122601010.
The previous prime is 1454122600991. The next prime is 1454122601017. The reversal of 1454122601011 is 1101062214541.
It is a strong prime.
It is an emirp because it is prime and its reverse (1101062214541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1454122601011 - 211 = 1454122598963 is a prime.
It is a super-2 number, since 2×14541226010112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1454122601017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 727061300505 + 727061300506.
It is an arithmetic number, because the mean of its divisors is an integer number (727061300506).
Almost surely, 21454122601011 is an apocalyptic number.
1454122601011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1454122601011 is an equidigital number, since it uses as much as digits as its factorization.
1454122601011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1920, while the sum is 28.
Adding to 1454122601011 its reverse (1101062214541), we get a palindrome (2555184815552).
The spelling of 1454122601011 in words is "one trillion, four hundred fifty-four billion, one hundred twenty-two million, six hundred one thousand, eleven".
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