Base | Representation |
---|---|
bin | 1000011101101101000… |
… | …0110010101101110111 |
3 | 111220100001100001100111 |
4 | 2013123100302231313 |
5 | 4340301102024421 |
6 | 150445051123451 |
7 | 13335313065136 |
oct | 2073320625567 |
9 | 456301301314 |
10 | 145412533111 |
11 | 5673a6473aa |
12 | 24222443587 |
13 | 1093502ca01 |
14 | 70763d791d |
15 | 3bb0eb4ee1 |
hex | 21db432b77 |
145412533111 has 4 divisors (see below), whose sum is σ = 145443816000. Its totient is φ = 145381250224.
The previous prime is 145412533099. The next prime is 145412533121. The reversal of 145412533111 is 111335214541.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 145412533111 - 217 = 145412402039 is a prime.
It is a super-2 number, since 2×1454125331112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (145412533121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15634471 + ... + 15643768.
It is an arithmetic number, because the mean of its divisors is an integer number (36360954000).
Almost surely, 2145412533111 is an apocalyptic number.
145412533111 is a deficient number, since it is larger than the sum of its proper divisors (31282889).
145412533111 is an equidigital number, since it uses as much as digits as its factorization.
145412533111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31282888.
The product of its digits is 7200, while the sum is 31.
Adding to 145412533111 its reverse (111335214541), we get a palindrome (256747747652).
The spelling of 145412533111 in words is "one hundred forty-five billion, four hundred twelve million, five hundred thirty-three thousand, one hundred eleven".
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