Base | Representation |
---|---|
bin | 100001000100000100110010… |
… | …111110100110100011110011 |
3 | 201001212120222121110222102121 |
4 | 201010010302332212203303 |
5 | 123024442033112343324 |
6 | 1233134553141055111 |
7 | 42425633132260114 |
oct | 4104046276464363 |
9 | 631776877428377 |
10 | 145415563012339 |
11 | 42374437387674 |
12 | 143866159b7497 |
13 | 631a8234a7229 |
14 | 27ca217b3620b |
15 | 11c28d4a7e5e4 |
hex | 844132fa68f3 |
145415563012339 has 2 divisors, whose sum is σ = 145415563012340. Its totient is φ = 145415563012338.
The previous prime is 145415563012261. The next prime is 145415563012471. The reversal of 145415563012339 is 933210365514541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 145415563012339 - 225 = 145415529457907 is a prime.
It is a super-2 number, since 2×1454155630123392 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (145415563015339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72707781506169 + 72707781506170.
It is an arithmetic number, because the mean of its divisors is an integer number (72707781506170).
Almost surely, 2145415563012339 is an apocalyptic number.
145415563012339 is a deficient number, since it is larger than the sum of its proper divisors (1).
145415563012339 is an equidigital number, since it uses as much as digits as its factorization.
145415563012339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832000, while the sum is 52.
The spelling of 145415563012339 in words is "one hundred forty-five trillion, four hundred fifteen billion, five hundred sixty-three million, twelve thousand, three hundred thirty-nine".
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