Base | Representation |
---|---|
bin | 1101001110100010100101… |
… | …1111101011011100101101 |
3 | 1220111100012102012110120121 |
4 | 3103220221133223130231 |
5 | 3401234444042401131 |
6 | 50533100551044541 |
7 | 3030505245336055 |
oct | 323505137533455 |
9 | 56440172173517 |
10 | 14543455434541 |
11 | 46a793249a250 |
12 | 176a751970751 |
13 | 816598cb8ca7 |
14 | 383c9ab3a565 |
15 | 1a3496a70911 |
hex | d3a297eb72d |
14543455434541 has 16 divisors (see below), whose sum is σ = 16268391639360. Its totient is φ = 12889721940480.
The previous prime is 14543455434533. The next prime is 14543455434631.
14543455434541 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 14543455434541 - 23 = 14543455434533 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14543455434341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 101646646 + ... + 101789623.
It is an arithmetic number, because the mean of its divisors is an integer number (1016774477460).
Almost surely, 214543455434541 is an apocalyptic number.
14543455434541 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
14543455434541 is a deficient number, since it is larger than the sum of its proper divisors (1724936204819).
14543455434541 is a wasteful number, since it uses less digits than its factorization.
14543455434541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 203436444.
The product of its digits is 23040000, while the sum is 52.
It can be divided in two parts, 1454345 and 5434541, that added together give a palindrome (6888886).
The spelling of 14543455434541 in words is "fourteen trillion, five hundred forty-three billion, four hundred fifty-five million, four hundred thirty-four thousand, five hundred forty-one".
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