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145443122053 = 148919767183
BaseRepresentation
bin1000011101110100010…
…1011110101110000101
3111220102011220010111021
42013131011132232011
54340331414401203
6150452102511141
713336134065545
oct2073505365605
9456364803437
10145443122053
115675593a319
12242307354b1
131093b47ca88
14707a4bb325
153bb3a085bd
hex21dd15eb85

145443122053 has 4 divisors (see below), whose sum is σ = 145452904128. Its totient is φ = 145433339980.

The previous prime is 145443122047. The next prime is 145443122063. The reversal of 145443122053 is 350221344541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 145443122053 - 221 = 145441024901 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145443122063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4868701 + ... + 4898482.

It is an arithmetic number, because the mean of its divisors is an integer number (36363226032).

Almost surely, 2145443122053 is an apocalyptic number.

It is an amenable number.

145443122053 is a deficient number, since it is larger than the sum of its proper divisors (9782075).

145443122053 is an equidigital number, since it uses as much as digits as its factorization.

145443122053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9782074.

The product of its (nonzero) digits is 57600, while the sum is 34.

Adding to 145443122053 its reverse (350221344541), we get a palindrome (495664466594).

The spelling of 145443122053 in words is "one hundred forty-five billion, four hundred forty-three million, one hundred twenty-two thousand, fifty-three".

Divisors: 1 14891 9767183 145443122053