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145453130015 = 529090626003
BaseRepresentation
bin1000011101110110101…
…1101010000100011111
3111220102212201120211112
42013131223222010133
54340342000130030
6150453101212235
713336315130354
oct2073553520437
9456385646745
10145453130015
1156760555466
1224233b6107b
131094057514b
14707b96462b
153bb4833a95
hex21ddaea11f

145453130015 has 4 divisors (see below), whose sum is σ = 174543756024. Its totient is φ = 116362504008.

The previous prime is 145453130003. The next prime is 145453130071. The reversal of 145453130015 is 510031354541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 510031354541 = 751679136291.

It is a cyclic number.

It is not a de Polignac number, because 145453130015 - 24 = 145453129999 is a prime.

It is a super-2 number, since 2×1454531300152 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14545312997 + ... + 14545313006.

It is an arithmetic number, because the mean of its divisors is an integer number (43635939006).

Almost surely, 2145453130015 is an apocalyptic number.

145453130015 is a deficient number, since it is larger than the sum of its proper divisors (29090626009).

145453130015 is an equidigital number, since it uses as much as digits as its factorization.

145453130015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29090626008.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 145453130015 its reverse (510031354541), we get a palindrome (655484484556).

The spelling of 145453130015 in words is "one hundred forty-five billion, four hundred fifty-three million, one hundred thirty thousand, fifteen".

Divisors: 1 5 29090626003 145453130015