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14545705075177 is a prime number
BaseRepresentation
bin1101001110101010111110…
…0101011000000111101001
31220111120000012022001101011
43103222233211120013221
53401304100444401202
650534112112423521
73030615063065113
oct323525745300751
956446005261334
1014545705075177
1146a8887344591
12176b07b247ba1
138168670ab2b3
1438403181a3b3
151a35792e5bd7
hexd3aaf9581e9

14545705075177 has 2 divisors, whose sum is σ = 14545705075178. Its totient is φ = 14545705075176.

The previous prime is 14545705075159. The next prime is 14545705075273. The reversal of 14545705075177 is 77157050754541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8861242982656 + 5684462092521 = 2976784^2 + 2384211^2 .

It is a cyclic number.

It is not a de Polignac number, because 14545705075177 - 235 = 14511345336809 is a prime.

It is a super-3 number, since 3×145457050751773 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (14545705055177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7272852537588 + 7272852537589.

It is an arithmetic number, because the mean of its divisors is an integer number (7272852537589).

Almost surely, 214545705075177 is an apocalyptic number.

It is an amenable number.

14545705075177 is a deficient number, since it is larger than the sum of its proper divisors (1).

14545705075177 is an equidigital number, since it uses as much as digits as its factorization.

14545705075177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24010000, while the sum is 58.

The spelling of 14545705075177 in words is "fourteen trillion, five hundred forty-five billion, seven hundred five million, seventy-five thousand, one hundred seventy-seven".