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145503300422033 is a prime number
BaseRepresentation
bin100001000101010110100000…
…100010010000100110010001
3201002011222110011220012010222
4201011112200202100212101
5123032411224402001113
61233243143214202425
742435160266041351
oct4105264042204621
9632158404805128
10145503300422033
11423a866a909114
121439b620ab3415
136325b96621b78
1427d057c342b61
1511c4d1c478e08
hex8455a0890991

145503300422033 has 2 divisors, whose sum is σ = 145503300422034. Its totient is φ = 145503300422032.

The previous prime is 145503300421957. The next prime is 145503300422041. The reversal of 145503300422033 is 330224003305541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113514683822929 + 31988616599104 = 10654327^2 + 5655848^2 .

It is a cyclic number.

It is not a de Polignac number, because 145503300422033 - 220 = 145503299373457 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 145503300421984 and 145503300422002.

It is not a weakly prime, because it can be changed into another prime (145503300422533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72751650211016 + 72751650211017.

It is an arithmetic number, because the mean of its divisors is an integer number (72751650211017).

Almost surely, 2145503300422033 is an apocalyptic number.

It is an amenable number.

145503300422033 is a deficient number, since it is larger than the sum of its proper divisors (1).

145503300422033 is an equidigital number, since it uses as much as digits as its factorization.

145503300422033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 145503300422033 its reverse (330224003305541), we get a palindrome (475727303727574).

The spelling of 145503300422033 in words is "one hundred forty-five trillion, five hundred three billion, three hundred million, four hundred twenty-two thousand, thirty-three".