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14550433403 = 1113923334079
BaseRepresentation
bin11011000110100010…
…11111111001111011
31101120001012121020212
431203101133321323
5214244402332103
610403454141335
71023400433432
oct154321377173
941501177225
1014550433403
116197381a80
1229a0ab184b
1314ab67170c
149c063a119
155a260e7d8
hex36345fe7b

14550433403 has 16 divisors (see below), whose sum is σ = 15998169600. Its totient is φ = 13123656480.

The previous prime is 14550433393. The next prime is 14550433411. The reversal of 14550433403 is 30433405541.

It is not a de Polignac number, because 14550433403 - 28 = 14550433147 is a prime.

It is a super-2 number, since 2×145504334032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14550433403.

It is not an unprimeable number, because it can be changed into a prime (14550433423) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3565118 + ... + 3569196.

It is an arithmetic number, because the mean of its divisors is an integer number (999885600).

Almost surely, 214550433403 is an apocalyptic number.

14550433403 is a deficient number, since it is larger than the sum of its proper divisors (1447736197).

14550433403 is a wasteful number, since it uses less digits than its factorization.

14550433403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6562.

The product of its (nonzero) digits is 43200, while the sum is 32.

Adding to 14550433403 its reverse (30433405541), we get a palindrome (44983838944).

The spelling of 14550433403 in words is "fourteen billion, five hundred fifty million, four hundred thirty-three thousand, four hundred three".

Divisors: 1 11 139 1529 2333 4079 25663 44869 324287 566981 3567157 6236791 9516307 104679377 1322766673 14550433403