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145525261311401 is a prime number
BaseRepresentation
bin100001000101101010111101…
…100000011001110110101001
3201002021002010200011221220212
4201011222331200121312221
5123033241213343431101
61233301214312230505
742436565431365026
oct4105527540316651
9632232120157825
10145525261311401
1142406a0a1a1364
12143a392b69b435
136327c8632c06a
1427d1662c2254d
1511c56a542e1bb
hex845abd819da9

145525261311401 has 2 divisors, whose sum is σ = 145525261311402. Its totient is φ = 145525261311400.

The previous prime is 145525261311373. The next prime is 145525261311467. The reversal of 145525261311401 is 104113162525541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 144120145050025 + 1405116261376 = 12005005^2 + 1185376^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145525261311401 is a prime.

It is not a weakly prime, because it can be changed into another prime (145525261313401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72762630655700 + 72762630655701.

It is an arithmetic number, because the mean of its divisors is an integer number (72762630655701).

Almost surely, 2145525261311401 is an apocalyptic number.

It is an amenable number.

145525261311401 is a deficient number, since it is larger than the sum of its proper divisors (1).

145525261311401 is an equidigital number, since it uses as much as digits as its factorization.

145525261311401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 41.

The spelling of 145525261311401 in words is "one hundred forty-five trillion, five hundred twenty-five billion, two hundred sixty-one million, three hundred eleven thousand, four hundred one".