Base | Representation |
---|---|
bin | 1000011110001010000… |
… | …1110110101001111011 |
3 | 111220122112201212200012 |
4 | 2013202201312221323 |
5 | 4341023304234303 |
6 | 150505124132135 |
7 | 13341323244656 |
oct | 2074241665173 |
9 | 456575655605 |
10 | 145534446203 |
11 | 567a2445523 |
12 | 2425723704b |
13 | 10954376633 |
14 | 708869089d |
15 | 3bbba475d8 |
hex | 21e2876a7b |
145534446203 has 2 divisors, whose sum is σ = 145534446204. Its totient is φ = 145534446202.
The previous prime is 145534446163. The next prime is 145534446217. The reversal of 145534446203 is 302644435541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 145534446203 - 26 = 145534446139 is a prime.
It is a super-2 number, since 2×1455344462032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (145534446263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72767223101 + 72767223102.
It is an arithmetic number, because the mean of its divisors is an integer number (72767223102).
Almost surely, 2145534446203 is an apocalyptic number.
145534446203 is a deficient number, since it is larger than the sum of its proper divisors (1).
145534446203 is an equidigital number, since it uses as much as digits as its factorization.
145534446203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 691200, while the sum is 41.
The spelling of 145534446203 in words is "one hundred forty-five billion, five hundred thirty-four million, four hundred forty-six thousand, two hundred three".
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