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145540101013 = 479303841547
BaseRepresentation
bin1000011110001011011…
…1011011001110010101
3111220122221101011121121
42013202313123032111
54341031231213023
6150505445243541
713341422306206
oct2074267331625
9456587334547
10145540101013
11567a565801a
12242591035b1
13109555a6488
1470893235ad
153bbc2b2d5d
hex21e2ddb395

145540101013 has 4 divisors (see below), whose sum is σ = 145843943040. Its totient is φ = 145236258988.

The previous prime is 145540100963. The next prime is 145540101043. The reversal of 145540101013 is 310101045541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 145540101013 - 229 = 145003230101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145540101043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151920295 + ... + 151921252.

It is an arithmetic number, because the mean of its divisors is an integer number (36460985760).

Almost surely, 2145540101013 is an apocalyptic number.

It is an amenable number.

145540101013 is a deficient number, since it is larger than the sum of its proper divisors (303842027).

145540101013 is an equidigital number, since it uses as much as digits as its factorization.

145540101013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 303842026.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 145540101013 its reverse (310101045541), we get a palindrome (455641146554).

The spelling of 145540101013 in words is "one hundred forty-five billion, five hundred forty million, one hundred one thousand, thirteen".

Divisors: 1 479 303841547 145540101013