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145556524481 is a prime number
BaseRepresentation
bin1000011110001111011…
…0000100110111000001
3111220201002021120101012
42013203312010313001
54341044432240411
6150511233250305
713342012021064
oct2074366046701
9456632246335
10145556524481
1156803955235
1224262703995
1310958b069c4
14708b59a8db
153bbd95918b
hex21e3d84dc1

145556524481 has 2 divisors, whose sum is σ = 145556524482. Its totient is φ = 145556524480.

The previous prime is 145556524459. The next prime is 145556524537. The reversal of 145556524481 is 184425655541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104445312400 + 41111212081 = 323180^2 + 202759^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145556524481 is a prime.

It is a super-2 number, since 2×1455565244812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145556524411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72778262240 + 72778262241.

It is an arithmetic number, because the mean of its divisors is an integer number (72778262241).

Almost surely, 2145556524481 is an apocalyptic number.

It is an amenable number.

145556524481 is a deficient number, since it is larger than the sum of its proper divisors (1).

145556524481 is an equidigital number, since it uses as much as digits as its factorization.

145556524481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3840000, while the sum is 50.

The spelling of 145556524481 in words is "one hundred forty-five billion, five hundred fifty-six million, five hundred twenty-four thousand, four hundred eighty-one".