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145652654353 is a prime number
BaseRepresentation
bin1000011110100110010…
…0110010000100010001
3111220221210011110202211
42013221210302010101
54341244034414403
6150524545512121
713344260064103
oct2075144620421
9456853143684
10145652654353
1156853143008
122428a942641
13109729c3a9b
14709a261573
153bc70e706d
hex21e9932111

145652654353 has 2 divisors, whose sum is σ = 145652654354. Its totient is φ = 145652654352.

The previous prime is 145652654347. The next prime is 145652654387. The reversal of 145652654353 is 353456256541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95933911824 + 49718742529 = 309732^2 + 222977^2 .

It is a cyclic number.

It is not a de Polignac number, because 145652654353 - 25 = 145652654321 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 145652654297 and 145652654306.

It is not a weakly prime, because it can be changed into another prime (145652654053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72826327176 + 72826327177.

It is an arithmetic number, because the mean of its divisors is an integer number (72826327177).

Almost surely, 2145652654353 is an apocalyptic number.

It is an amenable number.

145652654353 is a deficient number, since it is larger than the sum of its proper divisors (1).

145652654353 is an equidigital number, since it uses as much as digits as its factorization.

145652654353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6480000, while the sum is 49.

The spelling of 145652654353 in words is "one hundred forty-five billion, six hundred fifty-two million, six hundred fifty-four thousand, three hundred fifty-three".