Base | Representation |
---|---|
bin | 100001001000101101011110… |
… | …111101100000101010010001 |
3 | 201010000001020222122200011021 |
4 | 201020231132331200222101 |
5 | 123100201443344102231 |
6 | 1233541200121115441 |
7 | 42460641363255622 |
oct | 4110553675405221 |
9 | 633001228580137 |
10 | 145734128503441 |
11 | 42487551294145 |
12 | 14418300928b81 |
13 | 634189173b91a |
14 | 27db7d8827a49 |
15 | 11cad2c099811 |
hex | 848b5ef60a91 |
145734128503441 has 2 divisors, whose sum is σ = 145734128503442. Its totient is φ = 145734128503440.
The previous prime is 145734128503417. The next prime is 145734128503499. The reversal of 145734128503441 is 144305821437541.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 102894223655041 + 42839904848400 = 10143679^2 + 6545220^2 .
It is a cyclic number.
It is not a de Polignac number, because 145734128503441 - 215 = 145734128470673 is a prime.
It is not a weakly prime, because it can be changed into another prime (145734128501441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72867064251720 + 72867064251721.
It is an arithmetic number, because the mean of its divisors is an integer number (72867064251721).
Almost surely, 2145734128503441 is an apocalyptic number.
It is an amenable number.
145734128503441 is a deficient number, since it is larger than the sum of its proper divisors (1).
145734128503441 is an equidigital number, since it uses as much as digits as its factorization.
145734128503441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6451200, while the sum is 52.
The spelling of 145734128503441 in words is "one hundred forty-five trillion, seven hundred thirty-four billion, one hundred twenty-eight million, five hundred three thousand, four hundred forty-one".
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