Base | Representation |
---|---|
bin | 11011001011110000… |
… | …00100110001011001 |
3 | 1101200002101002222211 |
4 | 31211320010301121 |
5 | 214342042202223 |
6 | 10412054115121 |
7 | 1024440543262 |
oct | 154570046131 |
9 | 41602332884 |
10 | 14594100313 |
11 | 6209a97631 |
12 | 29b364baa1 |
13 | 14b7720320 |
14 | 9c6365969 |
15 | 5a6387d0d |
hex | 365e04c59 |
14594100313 has 24 divisors (see below), whose sum is σ = 16907300480. Its totient is φ = 12518288640.
The previous prime is 14594100281. The next prime is 14594100329. The reversal of 14594100313 is 31300149541.
It is not a de Polignac number, because 14594100313 - 25 = 14594100281 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14594100413) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 272218 + ... + 321388.
Almost surely, 214594100313 is an apocalyptic number.
14594100313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
14594100313 is a deficient number, since it is larger than the sum of its proper divisors (2313200167).
14594100313 is a wasteful number, since it uses less digits than its factorization.
14594100313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49297 (or 49280 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 31.
Adding to 14594100313 its reverse (31300149541), we get a palindrome (45894249854).
The spelling of 14594100313 in words is "fourteen billion, five hundred ninety-four million, one hundred thousand, three hundred thirteen".
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