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145994354766473 is a prime number
BaseRepresentation
bin100001001100011111110101…
…101001111011001010001001
3201010220220221121021111221012
4201030133311221323022021
5123113432414310011343
61234300514121053305
742515513132100413
oct4114376551731211
9633826847244835
10145994354766473
1142577949223144
121445a826027235
136360293339315
14280a2434599b3
1511d29aca67718
hex84c7f5a7b289

145994354766473 has 2 divisors, whose sum is σ = 145994354766474. Its totient is φ = 145994354766472.

The previous prime is 145994354766451. The next prime is 145994354766583. The reversal of 145994354766473 is 374667453499541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85186845227584 + 60807509538889 = 9229672^2 + 7797917^2 .

It is an emirp because it is prime and its reverse (374667453499541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 145994354766473 - 238 = 145719476859529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 145994354766394 and 145994354766403.

It is not a weakly prime, because it can be changed into another prime (145994354766373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72997177383236 + 72997177383237.

It is an arithmetic number, because the mean of its divisors is an integer number (72997177383237).

Almost surely, 2145994354766473 is an apocalyptic number.

It is an amenable number.

145994354766473 is a deficient number, since it is larger than the sum of its proper divisors (1).

145994354766473 is an equidigital number, since it uses as much as digits as its factorization.

145994354766473 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8230118400, while the sum is 77.

The spelling of 145994354766473 in words is "one hundred forty-five trillion, nine hundred ninety-four billion, three hundred fifty-four million, seven hundred sixty-six thousand, four hundred seventy-three".