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146000504051 is a prime number
BaseRepresentation
bin1000011111111001001…
…1101110010011110011
3111221212000201001211222
42013332103232103303
54343002112112201
6151023253255255
713356012544133
oct2077623562363
9457760631758
10146000504051
1156a115296a6
122436733452b
13109c9aa62cc
1470d052cac3
153be790891b
hex21fe4ee4f3

146000504051 has 2 divisors, whose sum is σ = 146000504052. Its totient is φ = 146000504050.

The previous prime is 146000504033. The next prime is 146000504057. The reversal of 146000504051 is 150405000641.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-146000504051 is a prime.

It is a super-2 number, since 2×1460005040512 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 146000504051.

It is not a weakly prime, because it can be changed into another prime (146000504057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73000252025 + 73000252026.

It is an arithmetic number, because the mean of its divisors is an integer number (73000252026).

Almost surely, 2146000504051 is an apocalyptic number.

146000504051 is a deficient number, since it is larger than the sum of its proper divisors (1).

146000504051 is an equidigital number, since it uses as much as digits as its factorization.

146000504051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 146000504051 its reverse (150405000641), we get a palindrome (296405504692).

The spelling of 146000504051 in words is "one hundred forty-six billion, five hundred four thousand, fifty-one".