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146034113 is a prime number
BaseRepresentation
bin10001011010001…
…00110111000001
3101011210022010212
420231010313001
5244341042423
622254003505
73422161301
oct1055046701
9334708125
10146034113
1175483655
1240aa6595
1324340a24
1415575601
15cc49578
hex8b44dc1

146034113 has 2 divisors, whose sum is σ = 146034114. Its totient is φ = 146034112.

The previous prime is 146034103. The next prime is 146034139. The reversal of 146034113 is 311430641.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132871729 + 13162384 = 11527^2 + 3628^2 .

It is an emirp because it is prime and its reverse (311430641) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 146034113 - 222 = 141839809 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (146034103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73017056 + 73017057.

It is an arithmetic number, because the mean of its divisors is an integer number (73017057).

Almost surely, 2146034113 is an apocalyptic number.

It is an amenable number.

146034113 is a deficient number, since it is larger than the sum of its proper divisors (1).

146034113 is an equidigital number, since it uses as much as digits as its factorization.

146034113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

The square root of 146034113 is about 12084.4574971324. The cubic root of 146034113 is about 526.6047502832.

Adding to 146034113 its reverse (311430641), we get a palindrome (457464754).

The spelling of 146034113 in words is "one hundred forty-six million, thirty-four thousand, one hundred thirteen".