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146263401233 is a prime number
BaseRepresentation
bin1000100000110111111…
…0100110001100010001
3111222112100101121222122
42020031332212030101
54344021412314413
6151105324144025
713365354253205
oct2101576461421
9458470347878
10146263401233
11570369711a4
122441b398015
1310a3c3b3181
147117404b05
153c10a39108
hex220dfa6311

146263401233 has 2 divisors, whose sum is σ = 146263401234. Its totient is φ = 146263401232.

The previous prime is 146263401217. The next prime is 146263401247. The reversal of 146263401233 is 332104362641.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129648964624 + 16614436609 = 360068^2 + 128897^2 .

It is a cyclic number.

It is not a de Polignac number, because 146263401233 - 24 = 146263401217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 146263401193 and 146263401202.

It is not a weakly prime, because it can be changed into another prime (146263401253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73131700616 + 73131700617.

It is an arithmetic number, because the mean of its divisors is an integer number (73131700617).

Almost surely, 2146263401233 is an apocalyptic number.

It is an amenable number.

146263401233 is a deficient number, since it is larger than the sum of its proper divisors (1).

146263401233 is an equidigital number, since it uses as much as digits as its factorization.

146263401233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 146263401233 its reverse (332104362641), we get a palindrome (478367763874).

The spelling of 146263401233 in words is "one hundred forty-six billion, two hundred sixty-three million, four hundred one thousand, two hundred thirty-three".