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146305103351 = 1113300463941
BaseRepresentation
bin1000100001000001110…
…1101011010111110111
3111222122020212022112112
42020100131223113313
54344113101301401
6151113414041235
713366401600551
oct2102035532767
9458566768475
10146305103351
1157058464660
122443134921b
1310a47c24694
14711cb7c4d1
153c145253bb
hex221076b5f7

146305103351 has 4 divisors (see below), whose sum is σ = 159605567304. Its totient is φ = 133004639400.

The previous prime is 146305103339. The next prime is 146305103377. The reversal of 146305103351 is 153301503641.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-146305103351 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (146305103311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6650231960 + ... + 6650231981.

It is an arithmetic number, because the mean of its divisors is an integer number (39901391826).

Almost surely, 2146305103351 is an apocalyptic number.

146305103351 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

146305103351 is a deficient number, since it is larger than the sum of its proper divisors (13300463953).

146305103351 is a wasteful number, since it uses less digits than its factorization.

146305103351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13300463952.

The product of its (nonzero) digits is 16200, while the sum is 32.

Adding to 146305103351 its reverse (153301503641), we get a palindrome (299606606992).

The spelling of 146305103351 in words is "one hundred forty-six billion, three hundred five million, one hundred three thousand, three hundred fifty-one".

Divisors: 1 11 13300463941 146305103351