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1463506661257 is a prime number
BaseRepresentation
bin10101010010111111110…
…010110110111110001001
312011220120021222110010221
4111102333302312332021
5142434230201130012
63040154202510041
7210510026236654
oct25227762667611
95156507873127
101463506661257
115147403a1903
121b7779505321
13a80149c3644
1450b96ab289b
1528108688507
hex154bfcb6f89

1463506661257 has 2 divisors, whose sum is σ = 1463506661258. Its totient is φ = 1463506661256.

The previous prime is 1463506661251. The next prime is 1463506661377. The reversal of 1463506661257 is 7521666053641.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1429198731081 + 34307930176 = 1195491^2 + 185224^2 .

It is a cyclic number.

It is not a de Polignac number, because 1463506661257 - 23 = 1463506661249 is a prime.

It is a super-2 number, since 2×14635066612572 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1463506661251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 731753330628 + 731753330629.

It is an arithmetic number, because the mean of its divisors is an integer number (731753330629).

Almost surely, 21463506661257 is an apocalyptic number.

It is an amenable number.

1463506661257 is a deficient number, since it is larger than the sum of its proper divisors (1).

1463506661257 is an equidigital number, since it uses as much as digits as its factorization.

1463506661257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5443200, while the sum is 52.

The spelling of 1463506661257 in words is "one trillion, four hundred sixty-three billion, five hundred six million, six hundred sixty-one thousand, two hundred fifty-seven".