Base | Representation |
---|---|
bin | 10101010011101011101… |
… | …000000000001110111101 |
3 | 12011222110112200012021000 |
4 | 111103223220000032331 |
5 | 142442231423404432 |
6 | 3040355152000513 |
7 | 210534165516642 |
oct | 25235350001675 |
9 | 5158415605230 |
10 | 1464242013117 |
11 | 514a88497614 |
12 | 1b7943830139 |
13 | a810115c9a0 |
14 | 50c2660ddc9 |
15 | 2814cee057c |
hex | 154eba003bd |
1464242013117 has 32 divisors (see below), whose sum is σ = 2336431986560. Its totient is φ = 900948821760.
The previous prime is 1464242013097. The next prime is 1464242013119. The reversal of 1464242013117 is 7113102424641.
1464242013117 is a `hidden beast` number, since 1 + 4 + 642 + 4 + 2 + 0 + 1 + 3 + 1 + 1 + 7 = 666.
It is not a de Polignac number, because 1464242013117 - 211 = 1464242011069 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1464242013119) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2319813 + ... + 2882709.
It is an arithmetic number, because the mean of its divisors is an integer number (73013499580).
Almost surely, 21464242013117 is an apocalyptic number.
It is an amenable number.
1464242013117 is a deficient number, since it is larger than the sum of its proper divisors (872189973443).
1464242013117 is a wasteful number, since it uses less digits than its factorization.
1464242013117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 570330 (or 570324 counting only the distinct ones).
The product of its (nonzero) digits is 32256, while the sum is 36.
Adding to 1464242013117 its reverse (7113102424641), we get a palindrome (8577344437758).
The spelling of 1464242013117 in words is "one trillion, four hundred sixty-four billion, two hundred forty-two million, thirteen thousand, one hundred seventeen".
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