Base | Representation |
---|---|
bin | 10101010011110101001… |
… | …010110111010111110011 |
3 | 12011222212200222211101021 |
4 | 111103311022313113303 |
5 | 142443043422144203 |
6 | 3040423112120311 |
7 | 210541151604001 |
oct | 25236512672763 |
9 | 5158780884337 |
10 | 1464402146803 |
11 | 51505a920402 |
12 | 1b7989396097 |
13 | a812839924b |
14 | 50c3d9b5a71 |
15 | 2815c0c25bd |
hex | 154f52b75f3 |
1464402146803 has 2 divisors, whose sum is σ = 1464402146804. Its totient is φ = 1464402146802.
The previous prime is 1464402146789. The next prime is 1464402146849. The reversal of 1464402146803 is 3086412044641.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1464402146803 - 229 = 1463865275891 is a prime.
It is a super-3 number, since 3×14644021468033 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 1464402146803.
It is not a weakly prime, because it can be changed into another prime (1464402146873) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 732201073401 + 732201073402.
It is an arithmetic number, because the mean of its divisors is an integer number (732201073402).
Almost surely, 21464402146803 is an apocalyptic number.
1464402146803 is a deficient number, since it is larger than the sum of its proper divisors (1).
1464402146803 is an equidigital number, since it uses as much as digits as its factorization.
1464402146803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 442368, while the sum is 43.
The spelling of 1464402146803 in words is "one trillion, four hundred sixty-four billion, four hundred two million, one hundred forty-six thousand, eight hundred three".
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