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1464403405042 = 2732201702521
BaseRepresentation
bin10101010011110101001…
…111101010100011110010
312011222212210100202100201
4111103311033222203302
5142443044232430132
63040423155105414
7210541165364224
oct25236517524362
95158783322321
101464403405042
115150605aa776
121b79898a226a
13a8128719b76
1450c3dc22414
152815c2702e7
hex154f53ea8f2

1464403405042 has 4 divisors (see below), whose sum is σ = 2196605107566. Its totient is φ = 732201702520.

The previous prime is 1464403405021. The next prime is 1464403405043. The reversal of 1464403405042 is 2405043044641.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1368148963041 + 96254442001 = 1169679^2 + 310249^2 .

It is a super-2 number, since 2×14644034050422 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1464403404992 and 1464403405010.

It is not an unprimeable number, because it can be changed into a prime (1464403405043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 366100851259 + ... + 366100851262.

Almost surely, 21464403405042 is an apocalyptic number.

1464403405042 is a deficient number, since it is larger than the sum of its proper divisors (732201702524).

1464403405042 is an equidigital number, since it uses as much as digits as its factorization.

1464403405042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 732201702523.

The product of its (nonzero) digits is 184320, while the sum is 37.

Adding to 1464403405042 its reverse (2405043044641), we get a palindrome (3869446449683).

The spelling of 1464403405042 in words is "one trillion, four hundred sixty-four billion, four hundred three million, four hundred five thousand, forty-two".

Divisors: 1 2 732201702521 1464403405042