Base | Representation |
---|---|
bin | 10101010011110101001… |
… | …111101010100011011101 |
3 | 12011222212210100202022221 |
4 | 111103311033222203131 |
5 | 142443044232430041 |
6 | 3040423155105341 |
7 | 210541165364164 |
oct | 25236517524335 |
9 | 5158783322287 |
10 | 1464403405021 |
11 | 5150605aa757 |
12 | 1b79898a2251 |
13 | a8128719b5b |
14 | 50c3dc223db |
15 | 2815c2702d1 |
hex | 154f53ea8dd |
1464403405021 has 2 divisors, whose sum is σ = 1464403405022. Its totient is φ = 1464403405020.
The previous prime is 1464403404991. The next prime is 1464403405043. The reversal of 1464403405021 is 1205043044641.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 972176280100 + 492227124921 = 985990^2 + 701589^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1464403405021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1464403405081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 732201702510 + 732201702511.
It is an arithmetic number, because the mean of its divisors is an integer number (732201702511).
Almost surely, 21464403405021 is an apocalyptic number.
It is an amenable number.
1464403405021 is a deficient number, since it is larger than the sum of its proper divisors (1).
1464403405021 is an equidigital number, since it uses as much as digits as its factorization.
1464403405021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 1464403405021 its reverse (1205043044641), we get a palindrome (2669446449662).
The spelling of 1464403405021 in words is "one trillion, four hundred sixty-four billion, four hundred three million, four hundred five thousand, twenty-one".
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