Base | Representation |
---|---|
bin | 10101010100100010010… |
… | …101111001000101101001 |
3 | 12012001211112001101011201 |
4 | 111110202111321011221 |
5 | 143001121430342022 |
6 | 3041030223524201 |
7 | 210566013421633 |
oct | 25244225710551 |
9 | 5161745041151 |
10 | 1465160012137 |
11 | 5154096a2898 |
12 | 1b7b5b159661 |
13 | a82193b8a83 |
14 | 50cb24d3a53 |
15 | 281a38c5127 |
hex | 15522579169 |
1465160012137 has 2 divisors, whose sum is σ = 1465160012138. Its totient is φ = 1465160012136.
The previous prime is 1465160012119. The next prime is 1465160012179. The reversal of 1465160012137 is 7312100615641.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1316857231936 + 148302780201 = 1147544^2 + 385101^2 .
It is an emirp because it is prime and its reverse (7312100615641) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1465160012137 is a prime.
It is a super-2 number, since 2×14651600121372 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1465160012096 and 1465160012105.
It is not a weakly prime, because it can be changed into another prime (1465160012837) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 732580006068 + 732580006069.
It is an arithmetic number, because the mean of its divisors is an integer number (732580006069).
Almost surely, 21465160012137 is an apocalyptic number.
It is an amenable number.
1465160012137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1465160012137 is an equidigital number, since it uses as much as digits as its factorization.
1465160012137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30240, while the sum is 37.
Adding to 1465160012137 its reverse (7312100615641), we get a palindrome (8777260627778).
The spelling of 1465160012137 in words is "one trillion, four hundred sixty-five billion, one hundred sixty million, twelve thousand, one hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •