Base | Representation |
---|---|
bin | 1101010100111111101001… |
… | …0111111000000101110001 |
3 | 1220212221101201210200111212 |
4 | 3111033322113320011301 |
5 | 3410044034001302323 |
6 | 51100035203445505 |
7 | 3041512025563136 |
oct | 325177227700561 |
9 | 56787351720455 |
10 | 14654334009713 |
11 | 473a960568942 |
12 | 1788136986895 |
13 | 823b8951a758 |
14 | 3893b88a058d |
15 | 1a62d5d61b78 |
hex | d53fa5f8171 |
14654334009713 has 2 divisors, whose sum is σ = 14654334009714. Its totient is φ = 14654334009712.
The previous prime is 14654334009709. The next prime is 14654334009779. The reversal of 14654334009713 is 31790043345641.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10253015333089 + 4401318676624 = 3202033^2 + 2097932^2 .
It is a cyclic number.
It is not a de Polignac number, because 14654334009713 - 22 = 14654334009709 is a prime.
It is not a weakly prime, because it can be changed into another prime (14654337009713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7327167004856 + 7327167004857.
It is an arithmetic number, because the mean of its divisors is an integer number (7327167004857).
Almost surely, 214654334009713 is an apocalyptic number.
It is an amenable number.
14654334009713 is a deficient number, since it is larger than the sum of its proper divisors (1).
14654334009713 is an equidigital number, since it uses as much as digits as its factorization.
14654334009713 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3265920, while the sum is 50.
The spelling of 14654334009713 in words is "fourteen trillion, six hundred fifty-four billion, three hundred thirty-four million, nine thousand, seven hundred thirteen".
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