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14654334009713 is a prime number
BaseRepresentation
bin1101010100111111101001…
…0111111000000101110001
31220212221101201210200111212
43111033322113320011301
53410044034001302323
651100035203445505
73041512025563136
oct325177227700561
956787351720455
1014654334009713
11473a960568942
121788136986895
13823b8951a758
143893b88a058d
151a62d5d61b78
hexd53fa5f8171

14654334009713 has 2 divisors, whose sum is σ = 14654334009714. Its totient is φ = 14654334009712.

The previous prime is 14654334009709. The next prime is 14654334009779. The reversal of 14654334009713 is 31790043345641.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10253015333089 + 4401318676624 = 3202033^2 + 2097932^2 .

It is a cyclic number.

It is not a de Polignac number, because 14654334009713 - 22 = 14654334009709 is a prime.

It is not a weakly prime, because it can be changed into another prime (14654337009713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7327167004856 + 7327167004857.

It is an arithmetic number, because the mean of its divisors is an integer number (7327167004857).

Almost surely, 214654334009713 is an apocalyptic number.

It is an amenable number.

14654334009713 is a deficient number, since it is larger than the sum of its proper divisors (1).

14654334009713 is an equidigital number, since it uses as much as digits as its factorization.

14654334009713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3265920, while the sum is 50.

The spelling of 14654334009713 in words is "fourteen trillion, six hundred fifty-four billion, three hundred thirty-four million, nine thousand, seven hundred thirteen".