Base | Representation |
---|---|
bin | 10101010111101100000… |
… | …001000000010000111110 |
3 | 12012101120022202002210112 |
4 | 111113230001000100332 |
5 | 143030034121043032 |
6 | 3042350052310022 |
7 | 211045610036366 |
oct | 25275401002076 |
9 | 5171508662715 |
10 | 1468543534142 |
11 | 5168955a3a73 |
12 | 1b8744312312 |
13 | a86383925b9 |
14 | 51113a119a6 |
15 | 283009751b2 |
hex | 155ec04043e |
1468543534142 has 4 divisors (see below), whose sum is σ = 2202815301216. Its totient is φ = 734271767070.
The previous prime is 1468543534103. The next prime is 1468543534153. The reversal of 1468543534142 is 2414353458641.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×14685435341423 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 367135883534 + ... + 367135883537.
It is an arithmetic number, because the mean of its divisors is an integer number (550703825304).
Almost surely, 21468543534142 is an apocalyptic number.
1468543534142 is a deficient number, since it is larger than the sum of its proper divisors (734271767074).
1468543534142 is an equidigital number, since it uses as much as digits as its factorization.
1468543534142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 734271767073.
The product of its digits is 5529600, while the sum is 50.
The spelling of 1468543534142 in words is "one trillion, four hundred sixty-eight billion, five hundred forty-three million, five hundred thirty-four thousand, one hundred forty-two".
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