Base | Representation |
---|---|
bin | 11011010111010110… |
… | …11001001001011001 |
3 | 1101220212112102211112 |
4 | 31223223121021121 |
5 | 220042002023233 |
6 | 10425452310105 |
7 | 1030032113144 |
oct | 155353311131 |
9 | 41825472745 |
10 | 14691439193 |
11 | 6259a30792 |
12 | 2a20172335 |
13 | 15019417b2 |
14 | 9d526305b |
15 | 5aebb4048 |
hex | 36bad9259 |
14691439193 has 2 divisors, whose sum is σ = 14691439194. Its totient is φ = 14691439192.
The previous prime is 14691439163. The next prime is 14691439199. The reversal of 14691439193 is 39193419641.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12676057744 + 2015381449 = 112588^2 + 44893^2 .
It is a cyclic number.
It is not a de Polignac number, because 14691439193 - 222 = 14687244889 is a prime.
It is a super-3 number, since 3×146914391933 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (14691439199) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7345719596 + 7345719597.
It is an arithmetic number, because the mean of its divisors is an integer number (7345719597).
Almost surely, 214691439193 is an apocalyptic number.
It is an amenable number.
14691439193 is a deficient number, since it is larger than the sum of its proper divisors (1).
14691439193 is an equidigital number, since it uses as much as digits as its factorization.
14691439193 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 629856, while the sum is 50.
The spelling of 14691439193 in words is "fourteen billion, six hundred ninety-one million, four hundred thirty-nine thousand, one hundred ninety-three".
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