Search a number
-
+
14699964377473 is a prime number
BaseRepresentation
bin1101010111101001101000…
…1001111010100110000001
31221001022011210101112120121
43111322122021322212001
53411321011340034343
651133023112540241
73045015551400244
oct325723211724601
957038153345517
1014699964377473
114758246733581
121794b503b1681
1382827bbca96b
1438b6a6b3d25b
151a75a6cbaaed
hexd5e9a27a981

14699964377473 has 2 divisors, whose sum is σ = 14699964377474. Its totient is φ = 14699964377472.

The previous prime is 14699964377447. The next prime is 14699964377491. The reversal of 14699964377473 is 37477346999641.

14699964377473 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8593762606144 + 6106201771329 = 2931512^2 + 2471073^2 .

It is a cyclic number.

It is not a de Polignac number, because 14699964377473 - 29 = 14699964376961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14699964377393 and 14699964377402.

It is not a weakly prime, because it can be changed into another prime (14699964377873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7349982188736 + 7349982188737.

It is an arithmetic number, because the mean of its divisors is an integer number (7349982188737).

Almost surely, 214699964377473 is an apocalyptic number.

It is an amenable number.

14699964377473 is a deficient number, since it is larger than the sum of its proper divisors (1).

14699964377473 is an equidigital number, since it uses as much as digits as its factorization.

14699964377473 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5184974592, while the sum is 79.

The spelling of 14699964377473 in words is "fourteen trillion, six hundred ninety-nine billion, nine hundred sixty-four million, three hundred seventy-seven thousand, four hundred seventy-three".