1470133311253 has 4 divisors (see below), whose sum is σ = 1471329515340. Its totient is φ = 1468937107168.

The previous prime is 1470133311247. The next prime is 1470133311263. The reversal of 1470133311253 is 3521133310741.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1461335246449 + 8798064804 = 1208857^2 + 93798^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1470133311253 is a prime.

It is a super-2 number, since 2×1470133311253² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1470133311203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 598100200 + ... + 598102657.

It is an arithmetic number, because the mean of its divisors is an integer number (367832378835).

Almost surely, 2^{1470133311253} is an apocalyptic number.

It is an amenable number.

1470133311253 is a deficient number, since it is larger than the sum of its proper divisors (1196204087).

1470133311253 is a wasteful number, since it uses less digits than its factorization.

1470133311253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1196204086.

The product of its (nonzero) digits is 22680, while the sum is 34.

Adding to 1470133311253 its reverse (3521133310741), we get a palindrome (4991266621994).

The spelling of 1470133311253 in words is "one trillion, four hundred seventy billion, one hundred thirty-three million, three hundred eleven thousand, two hundred fifty-three".