147111355053 has 24 divisors (see below), whose sum is σ = 235024754328. Its totient is φ = 88083303552.

The previous prime is 147111355051. The next prime is 147111355067. The reversal of 147111355053 is 350553111741.

147111355053 is a `hidden beast` number, since 1 + 4 + 7 + 11 + 135 + 505 + 3 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 4168380969 + 142942974084 = 64563^2 + 378078^2 .

It is not a de Polignac number, because 147111355053 - 2¹ = 147111355051 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 147111354999 and 147111355017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (147111355051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16987050 + ... + 16995707.

It is an arithmetic number, because the mean of its divisors is an integer number (9792698097).

Almost surely, 2^147111355053 is an apocalyptic number.

147111355053 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

147111355053 is a deficient number, since it is larger than the sum of its proper divisors (87913399275).

147111355053 is a wasteful number, since it uses less digits than its factorization.

147111355053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33982813 (or 33982810 counting only the distinct ones).

The product of its (nonzero) digits is 31500, while the sum is 36.

Adding to 147111355053 its reverse (350553111741), we get a palindrome (497664466794).

The spelling of 147111355053 in words is "one hundred forty-seven billion, one hundred eleven million, three hundred fifty-five thousand, fifty-three".