Base | Representation |
---|---|
bin | 11011011001101110… |
… | …10110001110111001 |
3 | 1101222021000000121021 |
4 | 31230313112032321 |
5 | 220112101201301 |
6 | 10431443142441 |
7 | 1030363261552 |
oct | 155467261671 |
9 | 41867000537 |
10 | 14711350201 |
11 | 626a1a0169 |
12 | 2a26974a21 |
13 | 1505ac3562 |
14 | 9d7b67329 |
15 | 5b17e88a1 |
hex | 36cdd63b9 |
14711350201 has 4 divisors (see below), whose sum is σ = 14714517904. Its totient is φ = 14708182500.
The previous prime is 14711350193. The next prime is 14711350243. The reversal of 14711350201 is 10205311741.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10205311741 = 72719 ⋅140339.
It is a cyclic number.
It is not a de Polignac number, because 14711350201 - 23 = 14711350193 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14711750201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1576875 + ... + 1586176.
It is an arithmetic number, because the mean of its divisors is an integer number (3678629476).
Almost surely, 214711350201 is an apocalyptic number.
It is an amenable number.
14711350201 is a deficient number, since it is larger than the sum of its proper divisors (3167703).
14711350201 is an equidigital number, since it uses as much as digits as its factorization.
14711350201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3167702.
The product of its (nonzero) digits is 840, while the sum is 25.
Adding to 14711350201 its reverse (10205311741), we get a palindrome (24916661942).
The spelling of 14711350201 in words is "fourteen billion, seven hundred eleven million, three hundred fifty thousand, two hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •