Base | Representation |
---|---|
bin | 11011011001101110… |
… | …10110001110110001 |
3 | 1101222021000000120222 |
4 | 31230313112032301 |
5 | 220112101201233 |
6 | 10431443142425 |
7 | 1030363261541 |
oct | 155467261661 |
9 | 41867000528 |
10 | 14711350193 |
11 | 626a1a0161 |
12 | 2a26974a15 |
13 | 1505ac3557 |
14 | 9d7b67321 |
15 | 5b17e8898 |
hex | 36cdd63b1 |
14711350193 has 2 divisors, whose sum is σ = 14711350194. Its totient is φ = 14711350192.
The previous prime is 14711350187. The next prime is 14711350243. The reversal of 14711350193 is 39105311741.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8287007089 + 6424343104 = 91033^2 + 80152^2 .
It is a cyclic number.
It is not a de Polignac number, because 14711350193 - 24 = 14711350177 is a prime.
It is a super-2 number, since 2×147113501932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14711350993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7355675096 + 7355675097.
It is an arithmetic number, because the mean of its divisors is an integer number (7355675097).
Almost surely, 214711350193 is an apocalyptic number.
It is an amenable number.
14711350193 is a deficient number, since it is larger than the sum of its proper divisors (1).
14711350193 is an equidigital number, since it uses as much as digits as its factorization.
14711350193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340, while the sum is 35.
The spelling of 14711350193 in words is "fourteen billion, seven hundred eleven million, three hundred fifty thousand, one hundred ninety-three".
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