Base | Representation |
---|---|
bin | 11011011010000001… |
… | …10100000101001001 |
3 | 1101222102200002122121 |
4 | 31231000310011021 |
5 | 220113220104003 |
6 | 10432012251241 |
7 | 1030423335445 |
oct | 155500640511 |
9 | 41872602577 |
10 | 14713831753 |
11 | 6270635635 |
12 | 2a27770b21 |
13 | 1506481c2a |
14 | 9d8211825 |
15 | 5b1b38cbd |
hex | 36d034149 |
14713831753 has 2 divisors, whose sum is σ = 14713831754. Its totient is φ = 14713831752.
The previous prime is 14713831733. The next prime is 14713831763. The reversal of 14713831753 is 35713831741.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9107266624 + 5606565129 = 95432^2 + 74877^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14713831753 is a prime.
It is not a weakly prime, because it can be changed into another prime (14713831733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7356915876 + 7356915877.
It is an arithmetic number, because the mean of its divisors is an integer number (7356915877).
Almost surely, 214713831753 is an apocalyptic number.
It is an amenable number.
14713831753 is a deficient number, since it is larger than the sum of its proper divisors (1).
14713831753 is an equidigital number, since it uses as much as digits as its factorization.
14713831753 is an evil number, because the sum of its binary digits is even.
The product of its digits is 211680, while the sum is 43.
The spelling of 14713831753 in words is "fourteen billion, seven hundred thirteen million, eight hundred thirty-one thousand, seven hundred fifty-three".
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