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147200153 is a prime number
BaseRepresentation
bin10001100011000…
…01100010011001
3101020222112122112
420301201202121
5300140401103
622335002105
73435115652
oct1061414231
9336875575
10147200153
11760aa721
1241369335
132465b6a9
141579a529
15cdc9cd8
hex8c61899

147200153 has 2 divisors, whose sum is σ = 147200154. Its totient is φ = 147200152.

The previous prime is 147200107. The next prime is 147200159. The reversal of 147200153 is 351002741.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138603529 + 8596624 = 11773^2 + 2932^2 .

It is a cyclic number.

It is not a de Polignac number, because 147200153 - 26 = 147200089 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (147200159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73600076 + 73600077.

It is an arithmetic number, because the mean of its divisors is an integer number (73600077).

Almost surely, 2147200153 is an apocalyptic number.

It is an amenable number.

147200153 is a deficient number, since it is larger than the sum of its proper divisors (1).

147200153 is an equidigital number, since it uses as much as digits as its factorization.

147200153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 147200153 is about 12132.6070158066. The cubic root of 147200153 is about 528.0026316539.

Adding to 147200153 its reverse (351002741), we get a palindrome (498202894).

The spelling of 147200153 in words is "one hundred forty-seven million, two hundred thousand, one hundred fifty-three".