Base | Representation |
---|---|
bin | 10101011010111100001… |
… | …101011011111011100001 |
3 | 12012201120202021211012212 |
4 | 111122330031123323201 |
5 | 143104212313012423 |
6 | 3044124425531505 |
7 | 211231302260501 |
oct | 25327415337341 |
9 | 5181522254185 |
10 | 1472036454113 |
11 | 518318225495 |
12 | 1b935a043b95 |
13 | a8a73c20454 |
14 | 51365889a01 |
15 | 28457434578 |
hex | 156bc35bee1 |
1472036454113 has 2 divisors, whose sum is σ = 1472036454114. Its totient is φ = 1472036454112.
The previous prime is 1472036454079. The next prime is 1472036454121. The reversal of 1472036454113 is 3114546302741.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1369782322129 + 102254131984 = 1170377^2 + 319772^2 .
It is a cyclic number.
It is not a de Polignac number, because 1472036454113 - 28 = 1472036453857 is a prime.
It is not a weakly prime, because it can be changed into another prime (1472030454113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 736018227056 + 736018227057.
It is an arithmetic number, because the mean of its divisors is an integer number (736018227057).
Almost surely, 21472036454113 is an apocalyptic number.
It is an amenable number.
1472036454113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1472036454113 is an equidigital number, since it uses as much as digits as its factorization.
1472036454113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 41.
The spelling of 1472036454113 in words is "one trillion, four hundred seventy-two billion, thirty-six million, four hundred fifty-four thousand, one hundred thirteen".
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