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147225689953 is a prime number
BaseRepresentation
bin1000100100011101010…
…1011011111101100001
3112002000102002221221121
42021013111123331201
54403004234034303
6151345021252241
713431250500526
oct2110725337541
9462012087847
10147225689953
1157490077a31
1224649704081
1310b63878494
1471a913714d
153c6a26b9bd
hex224755bf61

147225689953 has 2 divisors, whose sum is σ = 147225689954. Its totient is φ = 147225689952.

The previous prime is 147225689921. The next prime is 147225690071. The reversal of 147225689953 is 359986522741.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95445777249 + 51779912704 = 308943^2 + 227552^2 .

It is a cyclic number.

It is not a de Polignac number, because 147225689953 - 25 = 147225689921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 147225689891 and 147225689900.

It is not a weakly prime, because it can be changed into another prime (147225689153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73612844976 + 73612844977.

It is an arithmetic number, because the mean of its divisors is an integer number (73612844977).

Almost surely, 2147225689953 is an apocalyptic number.

It is an amenable number.

147225689953 is a deficient number, since it is larger than the sum of its proper divisors (1).

147225689953 is an equidigital number, since it uses as much as digits as its factorization.

147225689953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 32659200, while the sum is 61.

The spelling of 147225689953 in words is "one hundred forty-seven billion, two hundred twenty-five million, six hundred eighty-nine thousand, nine hundred fifty-three".