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1474413114103 = 13710762139519
BaseRepresentation
bin10101011101001001110…
…111101011001011110111
312012221201101101122210221
4111131021313223023313
5143124044224122403
63045200325555211
7211344221454406
oct25351167531367
95187641348727
101474413114103
115193278462a6
121b9901b75b07
13a9062426637
145150d39163d
1528545de9dbd
hex15749deb2f7

1474413114103 has 4 divisors (see below), whose sum is σ = 1485175253760. Its totient is φ = 1463650974448.

The previous prime is 1474413114089. The next prime is 1474413114113. The reversal of 1474413114103 is 3014113144741.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1474413114103 - 217 = 1474412983031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1474413114113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5381069623 + ... + 5381069896.

It is an arithmetic number, because the mean of its divisors is an integer number (371293813440).

Almost surely, 21474413114103 is an apocalyptic number.

1474413114103 is a deficient number, since it is larger than the sum of its proper divisors (10762139657).

1474413114103 is a wasteful number, since it uses less digits than its factorization.

1474413114103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10762139656.

The product of its (nonzero) digits is 16128, while the sum is 34.

Adding to 1474413114103 its reverse (3014113144741), we get a palindrome (4488526258844).

The spelling of 1474413114103 in words is "one trillion, four hundred seventy-four billion, four hundred thirteen million, one hundred fourteen thousand, one hundred three".

Divisors: 1 137 10762139519 1474413114103