Search a number
-
+
1475040466241 is a prime number
BaseRepresentation
bin10101011101101111010…
…000110101010101000001
312020000100002212110011022
4111131233100311111001
5143131340324404431
63045342500155225
7211365610043366
oct25355720652501
95200302773138
101475040466241
11519619986241
121b9a58098b15
13a91323aac14
145156c81846d
152858101c07b
hex1576f435541

1475040466241 has 2 divisors, whose sum is σ = 1475040466242. Its totient is φ = 1475040466240.

The previous prime is 1475040466157. The next prime is 1475040466261. The reversal of 1475040466241 is 1426640405741.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 890954761216 + 584085705025 = 943904^2 + 764255^2 .

It is an emirp because it is prime and its reverse (1426640405741) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1475040466241 - 234 = 1457860597057 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1475040466192 and 1475040466201.

It is not a weakly prime, because it can be changed into another prime (1475040466261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 737520233120 + 737520233121.

It is an arithmetic number, because the mean of its divisors is an integer number (737520233121).

Almost surely, 21475040466241 is an apocalyptic number.

It is an amenable number.

1475040466241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1475040466241 is an equidigital number, since it uses as much as digits as its factorization.

1475040466241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 645120, while the sum is 44.

The spelling of 1475040466241 in words is "one trillion, four hundred seventy-five billion, forty million, four hundred sixty-six thousand, two hundred forty-one".