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14761010141953 is a prime number
BaseRepresentation
bin1101011011001101000011…
…0001000001101100000001
31221021010202011202200111121
43112303100301001230001
53413321022044020303
651221040415312241
73052306410003055
oct326632061015401
957233664680447
1014761010141953
1147811224519a9
1217a494851b681
13830c5a1c95aa
14390618453c65
151a8e7b23e9bd
hexd6cd0c41b01

14761010141953 has 2 divisors, whose sum is σ = 14761010141954. Its totient is φ = 14761010141952.

The previous prime is 14761010141923. The next prime is 14761010142031. The reversal of 14761010141953 is 35914101016741.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7448707309824 + 7312302832129 = 2729232^2 + 2704127^2 .

It is an emirp because it is prime and its reverse (35914101016741) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14761010141953 - 25 = 14761010141921 is a prime.

It is not a weakly prime, because it can be changed into another prime (14761010141923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7380505070976 + 7380505070977.

It is an arithmetic number, because the mean of its divisors is an integer number (7380505070977).

Almost surely, 214761010141953 is an apocalyptic number.

It is an amenable number.

14761010141953 is a deficient number, since it is larger than the sum of its proper divisors (1).

14761010141953 is an equidigital number, since it uses as much as digits as its factorization.

14761010141953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90720, while the sum is 43.

The spelling of 14761010141953 in words is "fourteen trillion, seven hundred sixty-one billion, ten million, one hundred forty-one thousand, nine hundred fifty-three".