Base | Representation |
---|---|
bin | 1101011011001101000011… |
… | …0001000001101100000001 |
3 | 1221021010202011202200111121 |
4 | 3112303100301001230001 |
5 | 3413321022044020303 |
6 | 51221040415312241 |
7 | 3052306410003055 |
oct | 326632061015401 |
9 | 57233664680447 |
10 | 14761010141953 |
11 | 47811224519a9 |
12 | 17a494851b681 |
13 | 830c5a1c95aa |
14 | 390618453c65 |
15 | 1a8e7b23e9bd |
hex | d6cd0c41b01 |
14761010141953 has 2 divisors, whose sum is σ = 14761010141954. Its totient is φ = 14761010141952.
The previous prime is 14761010141923. The next prime is 14761010142031. The reversal of 14761010141953 is 35914101016741.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7448707309824 + 7312302832129 = 2729232^2 + 2704127^2 .
It is an emirp because it is prime and its reverse (35914101016741) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14761010141953 - 25 = 14761010141921 is a prime.
It is not a weakly prime, because it can be changed into another prime (14761010141923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7380505070976 + 7380505070977.
It is an arithmetic number, because the mean of its divisors is an integer number (7380505070977).
Almost surely, 214761010141953 is an apocalyptic number.
It is an amenable number.
14761010141953 is a deficient number, since it is larger than the sum of its proper divisors (1).
14761010141953 is an equidigital number, since it uses as much as digits as its factorization.
14761010141953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90720, while the sum is 43.
The spelling of 14761010141953 in words is "fourteen trillion, seven hundred sixty-one billion, ten million, one hundred forty-one thousand, nine hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •